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Python Python Basics (2015) Number Game App Squared

wayne ross
wayne ross
3,225 Points
Posted by wayne ross
wayne ross
3,225 Points

getting TypeError for inputs of arg1='8' instead of 64 when using return((arg1**2))

---python---

def squared(arg1): print('inside function') #print(arg1) #print((arg1)2) try: print('made it to try') int(arg1) print('Try was True') return((arg1*2))

except ValueError:

  print('made it to except')
  return (((arg1)*2))

'''except TypeError:
  x=int((arg1))

  return((x**2))'''

1 Answer

wayne ross
wayne ross
3,225 Points
wayne ross
wayne ross
3,225 Points 
def squared(arg1):
    try:
        int(arg1)
        return((arg1**2))

    except ValueError:
        return (((arg1)*(len(arg1))))

    except TypeError:
        newType_var=int(arg1)    
        return((newType_var**2))