Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript AJAX Basics AJAX Concepts A Simple AJAX Example

Pimwipha Cheaptumrong
Pimwipha Cheaptumrong
10,977 Points

A Simple AJAX Example (Problem)

Hi. I was trying to follow the AJAX Exercise. I checked my code and refresh the webpage for the result. It doesn't look the same as Dave did. There is no welcome message in webpage. Just only the headline. What is wrong with code or workspace? Thank you so much!


<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <link href='//fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'> <link rel="stylesheet" href="css/main.css"> <title>AJAX with JavaScript</title> <script> //create an XMLHttp Request Object var xhr = new XMLHttpRequest();

//create a callback function
xhr.onreadystatechange = function () {
  if (xhr.readyState === 4) {
    document.getElementByID('ajax').innerHTML = xhr.responseText;

//open a request
xhr.open('GET', 'sidebar.html');

//Send a request 

</script> </head> <body> <div class="grid-container centered"> <div class="grid-100"> <div class="contained"> <div class="grid-100"> <div class="heading"> <h1>Bring on the AJAX</h1> </div> <div id="ajax">


</div> </body> </html>

2 Answers

Hi Pimwipha, If you weren't able to figure this out it looks like you may have your code to create the XMLHTTPRequest() object commented out:

    <script> //create an XMLHttp Request Object var xhr = new XMLHttpRequest();

Hope this helped...

if(xhr.readyState === 4 ) { .... }