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JavaScript AJAX Basics AJAX Concepts A Simple AJAX Example

Pimwipha Cheaptumrong
Pimwipha Cheaptumrong
10,977 Points

A Simple AJAX Example (Problem)

Hi. I was trying to follow the AJAX Exercise. I checked my code and refresh the webpage for the result. It doesn't look the same as Dave did. There is no welcome message in webpage. Just only the headline. What is wrong with code or workspace? Thank you so much!

https://teamtreehouse.com/library/a-simple-ajax-example-2#questions

<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <link href='//fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'> <link rel="stylesheet" href="css/main.css"> <title>AJAX with JavaScript</title> <script> //create an XMLHttp Request Object var xhr = new XMLHttpRequest();

//create a callback function
xhr.onreadystatechange = function () {
  if (xhr.readyState === 4) {
    document.getElementByID('ajax').innerHTML = xhr.responseText;
  }
};

//open a request
xhr.open('GET', 'sidebar.html');

//Send a request 
xhr.send();

</script> </head> <body> <div class="grid-container centered"> <div class="grid-100"> <div class="contained"> <div class="grid-100"> <div class="heading"> <h1>Bring on the AJAX</h1> </div> <div id="ajax">

      </div>
    </div>
  </div>
</div>

</div> </body> </html>

2 Answers

Hi Pimwipha, If you weren't able to figure this out it looks like you may have your code to create the XMLHTTPRequest() object commented out:

    <script> //create an XMLHttp Request Object var xhr = new XMLHttpRequest();

Hope this helped...

if(xhr.readyState === 4 ) { .... }