Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Number Game App Even or Odd

Argument for if condition spits out a SyntaxError for my if num % 2 == 0

The only if condition I can think of is in my code below. Can't figure out any other way around it. Can someone help?


def even_odd(num):
    if num % 2 == 0
        return True
        return False

1 Answer

Steven Parker
Steven Parker
225,652 Points

It looks like you just forgot the colon (":") at the end of the "if" line.