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Python Python Basics (2015) Shopping List App Break

Philip Matunda
PLUS
Philip Matunda
Courses Plus Student 510 Points
Posted by Philip Matunda
Philip Matunda
Courses Plus Student 510 Points

break function

def loopy(items):


    #code goes here
    for item in items:
        print(item)
    if item =="STOP":
        break
    print(item) 

list=["apple", "orange", "STOP", "pears"]

loopy(list)

I've been trying to run the code but it's yielding a bummer

breaks.py 
def loopy(items):


    #code goes here
    for item in items:
        print(item)
    if item =="STOP":
        break
    print(item) 

list=["apple", "orange", "STOP", "pears"]

loopy(list)

1 Answer

Steve Hunter
Steve Hunter
57,712 Points

Hi Philip,

You have unindented your if statement so it is outside the forloop. Indent the if statement and the break by 4 spaces.

Also, only output the print after the if statement, but inside the loop. i.e. if item is 'STOP' nothing gets printed.

Steve.

Philip Matunda
Philip Matunda
Courses Plus Student 510 Points
Philip Matunda
Philip Matunda
Courses Plus Student 510 Points

is it something like this

def loopy(items):
    # Code goes here
    for item in items:
        print(item) # remove this line
        if item == 'STOP':
            break
            print (item) # unindent this by 4
Steve Hunter
Steve Hunter
57,712 Points

Nearly. Remove the first print statement - you want that after the if statement, but not within it. So, unindent the second print statement by 4 spaces - it needs to be inside the for loop but outside the if statement. Also, add brackets around item in your print statement.

Steve.

Steve Hunter
Steve Hunter
57,712 Points

I added some comments in your code.

Steve Hunter
Steve Hunter
57,712 Points

:+1: :+1: