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build a simple php application code challenge task 3 of 4

I can not seem to pass the 3rd task of the code challenge: build a simple php application. here is the question:

The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.

here's what I have:

$flavor = "cookie dough";
echo "<p>Your favorite flavor of ice cream is ";
echo "$flavor";
echo ".</p>";
if ($flavor == 'cookie dough';) {echo "<p>Randy's favorite flavor is cookie dough, also!</p>";};


can someone help me out, thanks!

6 Answers

Stone Preston
Stone Preston
42,016 Points
if ($flavor == 'cookie dough';) {echo "<p>Randy's favorite flavor is cookie dough, also!</p>";};

You have a semicolon at the end of the if statement block. Try removing that and see if it works

Hi Stone, I took that ; out and I passed. Thanks so much, I was stuck on that one for a while!

Julian Price
Julian Price
11,760 Points

I have been so stuck on this model too but at 2 of 4 of the variable and conditionals code challenge. I am not real clear what the question asking because i am using the if statements

The question is asking for you to use the variable that you created in task 1. So instead of line 4 saying

echo "vanilla";

you want it to echo your $flavor

Julian Price
Julian Price
11,760 Points

Thanks Aaron I finally completed. I had to come back after listening to later videos but did it.

Awesome! It's a good feeling when you get it right.