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Aaron Goldman
5,051 Pointsbuild a simple php application code challenge task 3 of 4
I can not seem to pass the 3rd task of the code challenge: build a simple php application. here is the question:
The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.
here's what I have:
<?php
$flavor = "cookie dough";
echo "<p>Your favorite flavor of ice cream is ";
echo "$flavor";
echo ".</p>";
if ($flavor == 'cookie dough';) {echo "<p>Randy's favorite flavor is cookie dough, also!</p>";};
?>
can someone help me out, thanks!
6 Answers
Stone Preston
42,016 Pointsif ($flavor == 'cookie dough';) {echo "<p>Randy's favorite flavor is cookie dough, also!</p>";};
You have a semicolon at the end of the if statement block. Try removing that and see if it works
Aaron Goldman
5,051 PointsHi Stone, I took that ; out and I passed. Thanks so much, I was stuck on that one for a while!
Stone Preston
42,016 Pointsno problem.
Julian Price
11,760 PointsI have been so stuck on this model too but at 2 of 4 of the variable and conditionals code challenge. I am not real clear what the question asking because i am using the if statements
Aaron Goldman
5,051 PointsThe question is asking for you to use the variable that you created in task 1. So instead of line 4 saying
echo "vanilla";
you want it to echo your $flavor
Julian Price
11,760 PointsThanks Aaron I finally completed. I had to come back after listening to later videos but did it.
Aaron Goldman
5,051 PointsAwesome! It's a good feeling when you get it right.