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Victor Purol
7,776 PointsBummer! Did you call send() on the request object?
I keep getting this error message though it seems clear i have called send on the request.
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
request.open('GET','footer.html');
function sendAjax(){
request.send();
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
2 Answers
Seth Kroger
56,413 PointsIt looks like you wrapped the send() call inside a function without calling the function. Try doing it without wrapping it inside a function.
Victor Purol
7,776 PointsThanks Seth! that was the issue.