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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Ankur Abichandani
Ankur Abichandani
182 Points

call the printf method to print "<your name> can code in Java!"

i am not able to execute this. below is what i am typing and below that is the error i receive.

String firstName = "Ankur"; console.printf= ("%s can code in Java!", firstName );

Error- JavaTester.java:74: error: cannot find symbol printf= ("%s can code in Java!"); ^ symbol: variable printf location: class JavaTester Note: JavaTester.java uses or overrides a deprecated API. Note: Recompile with -Xlint:deprecation for details. 1 error

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Ankur";
printf= ("%s can code in Java!");
JavaTester.java:74: error: cannot find symbol
printf= ("%s can code in Java!");
^
  symbol:   variable printf
  location: class JavaTester
Note: JavaTester.java uses or overrides a deprecated API.
Note: Recompile with -Xlint:deprecation for details.
1 error

1 Answer

Alexis Beliveau
Alexis Beliveau
8,029 Points
Alexis Beliveau
Alexis Beliveau
8,029 Points

System.out.printf ("%s can code in Java!" , firstName);

Seems you are missing System.out. Also, you have to list what the String in %s actually is.

This may help a little! (:

http://web.cerritos.edu/jwilson/SitePages/java_language_resources/Java_printf_method_quick_reference.pdf

Ankur Abichandani
Ankur Abichandani
182 Points

Thanks alexis. i found that i putting an "=" symbol after printf, rather than just printf ("%s can code in java!", fistname);