can someone help me with the Challenge Even/odd..? i dont no how to start...:(

Tnx Stuart !! understood.

The first line of your solution should be:

def even_odd(num):
    # your code goes here

What this does is define a function called even_odd, with one argument, num. From here, you need to write an if statement to return True if num is even, or False if num is odd. Good luck!

def even_odd(test) if test % 2 == 0: return True else: return False

i thing i got it.

but i dont know what the sing % using for ..

That looks like the correct solution.

The % symbol gives the remainder after dividing an integer by another integer.

So 11 % 4 = 3. Because 11 divided by 4 is 2, with 3 left over.

It works for your even_odd function because any even number % 2 will be 0, and any odd number % 2 will be 1.