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PHP Object-Oriented PHP Basics Building the Recipe Controlling the Class

Joshua Miles
Joshua Miles
545 Points
Posted by Joshua Miles
Joshua Miles
545 Points

communication error

I am continually getting a communication error whenever i click "check work". I would like to move on to the next section and its the only thing holding me back. help!

fish.php 
<?php

class Fish
{
    public $common_name;
    public $flavor;
    public $record_weight;
  function __construct($name, $flavor, $record){
   // $this->common_name = $name;
    //$this->flavor = $flavor; 
    //$this->record_weight = $record;
    $bass = new Fish();
    $bass->common_name = "Largemouth Bass";
    $bass->flavor = "Excellent";
    $bass->record_weight = "22 pounds 5 ounces";
   // $bass->getInfo("Largemouth Bass","Excellent","22 pounds 5 ounces");
  }

    public function getInfo() {
      return "A {$this->common_name} is an {$this->flavor} flavored fish. The world record weight is {$this->record_weight}.";
    }
}

?>

1 Answer

Brian Jensen
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree seal-36
Brian Jensen
Treehouse Staff
Brian Jensen
.a{fill-rule:evenodd;}techdegree seal-36
Brian Jensen
Treehouse Staff

When you instantiate a class you have to be outside of it, you were still inside of fish.

<?php

class Fish
{
    public $common_name;
    public $flavor;
    public $record_weight;

    function __construct($name, $flavor, $record){
    $this->common_name = $name;
    $this->flavor = $flavor;
    $this->record_weight = $record;
    }

    public function getInfo() {
      return "A {$this->common_name} is an {$this->flavor} flavored fish. The world record weight is {$this->record_weight}.";
    }
}

$bass = new Fish("Largemouth Bass","Excellent","22 pounds 5 ounces");

?>