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Akshat Jain
6,810 PointsCompletely lost on the last challenge
Here is something I attempted
# combo(['swallow', 'snake', 'parrot'], 'abc')
# Output:
# [('swallow', 'a'), ('snake', 'b'), ('parrot', 'c')]
# If you use list.append(), you'll want to pass it a tuple of new values.
# Using enumerate() here can save you a variable or two.
def combo(x, y):
count = 0
for i in enumerate(x):
return x, y[count]
count += 1
1 Answer
Kenneth Love
Treehouse Guest TeacherIt's a good start. The return will make the count += 1 not ever happen, though.
Using enumerate is a good idea. Remember, enumerate returns you a tuple of the current index and the current value. How could you use that index to get the same-indexed item in the other iterable? Also, you need to be building a list that'll get returned in the end, not just returning the first tuple.