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JavaScript JavaScript Basics Making Decisions in Your Code with Conditional Statements Use Comparison Operators

Samuel Bueno
Samuel Bueno
767 Points

conditional stetament test

const a = 10;
const b = 20;
const c = 30;

if ( const b > const a ) {
  console.log("a is greater than b");
} else {
  conaole.log("a is not greater than b");
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
<script src="js/conditionals.js"></script>

3 Answers

Hello, Samuel!

You've posted this question a few times now, and I've put an answer on the first post. I went into the coding challenge and tried it myself to make sure it worked.

I hope this helps!

I'll re-post my answer here so it's easier:

You are trying to create the same variable twice, I think! "const" should only be called when you are first creating the constant variable. So, for example:

const a = 10;

After this, "a" can just be referred to as "a". In your if statement, you have written "const" before the variables again. You only need to write the variable name to reference them!

I hope this helps!

Haha, Yeah, It's such the slightest, could be missed by anyone

Your spelling of console is not correct, in else statement. Also no need to write const a, const b in if condition, they are already declared above.

Also would have helped if I noticed "conaole"... Thank you for being more concise and accurate, haha!

Samuel Bueno
Samuel Bueno
767 Points

it is not working, I don't know what's going on!