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PHP PHP Basics Daily Exercise Program Conditionals

Conditionals in PHP

Hello!

I am stuck on this one question, and I can't seem to figure it out.

In the exercise for Conditionals in the PHP course, the instructions are as follows:

"Check if each student has a GPA of 4.0.

If the student has a GPA of 4.0, use the student name variable to replace NAME when displaying the following line:

NAME made the Honor Roll

ELSE If the students GPA is not equal to 4.0, within an else block, use the student name variable to replace NAME AND the student GPA variable to replace STUDENT GPA when displaying the following line:

NAME has a GPA of STUDENT GPA"

When typing out my code, the preview prints out the results in one line. When clicking on "Check Work" I get the message: "Bummer: Use the variables to display the message"

I am unsure which variables it is referring to, as I was confident to have used the required ones. But, clearly, I am doing something wrong. Can anyone point me in the right direction?

index.php
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment

if ($studentOneGPA == 4.0){
  echo "$studentOneName made the Honor Roll\n";
} 
else{
  echo "$studentOneName has a GPA of $studentOneGPA\n";
}

if ($studentTwoGPA == 4.0){
  echo "$studentTwoName made the Honor Roll\n";
}
else{
  echo "$studentOneName has a GPA of $studentOneGPA\n";
}

?>

2 Answers

Look at your last else block, $studentOneName and $studentOneGPA should be $studentTwoName and $studentTwoGPA.

Oh my! That is so embarrassing. Lesson learned: don't be lazy and copy and paste mindlessly. Thanks for the quick answer, appreciate that.