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JavaScript Manage Multiple Requests with Promise.all

2 Answers

Steven Parker
Steven Parker
231,184 Points

On line 35, there's a call to "Promise.resolve" with no argument. But it should be:

        return Promise.resolve(response);

How can I solve "content.js:2 Uncaught (in promise) TypeError: Cannot read properties of undefined (reading 'debugMode')"

const select = document.getElementById('breeds'); const card = document.querySelector('.card'); const form = document.querySelector('form');

// ------------------------------------------ // FETCH FUNCTIONS // ------------------------------------------ function fetchData(url){ return fetch(url) .then(checkStatus) .then(res=>res.json()) .catch(error => console.log('Looks like there was a problem',error)) }

Promise.all([ fetchData('https://dog.ceo/api/breeds/list'), fetchData('https://dog.ceo/api/breeds/image/random')

]) .then(data =>{ const breadList = data[0].message; const randomImage = data[1].message;

 generateOperations(breadList);
 generateImage(randomImage);

 })         

// ------------------------------------------ // HELPER FUNCTIONS // ------------------------------------------ function checkStatus(response){ if (response.ok){ return Promise.resolve(response); }else{ return Promise.reject(new Error(response.statusText));statusText }

}

function generateImage(data){ const html =`

<img src="${data}" alt="${select.value}s">

<p>Click to view images of ${select.value}s</p>`;

card.innerHTML =html; }

function generateOptions(data){ const options =data.map(item=> <option value="${item}">${item}</option>).join('');

select.innerHTML =options; }

function fetchBreedImage(){ const breed = select.value; const img = card.querySelector('img'); const p = card.querySelector('p');

fetchData(https://dog.ceo/api/breed/${breed}/images/random) .then(data =>{ img.src=data.message; img.alt= breed; p.textContent=Click to view more ${breed}s; });

}

// ------------------------------------------ // EVENT LISTENERS // ------------------------------------------ select.addEventListener('change',fetchBreedImage); card.addEventListener('click',fetchBreedImage);

Steven Parker
Steven Parker
231,184 Points

When you need help, always create a new question instead of posting one as an answer or comment to someone else's. And for sharing your code, make a snapshot of your workspace and post the link to it (as was done by the original poster).