Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Number Game App Even or Odd

def even_odd (number): if number % 2 == 0 : return True else: return False

what him I doing that it is not working???

def even_odd (number):
if number % 2 == 0 :
    return True
    return False 
Michael Caveney
Michael Caveney
50,144 Points

Have you double-checked indentation? That looks off to me, maybe move everything under the function definition to the right?

EDIT: Yeah, it's definitely your indentation.

2 Answers

jason chan
jason chan
31,009 Points

that should be right. please check spacing.

Michael Caveney
Michael Caveney
50,144 Points

Oh yeah, did you indent using a mix of spaces and tabs? That might have done it.

Well the Problem is that the code is not like that a take a time to to understand it should be like this. I think the exercise is not clearly!!!

import random
start = 5
def even_odd(num, cont):
    while cont:
        rand = random.randint(1, 99)
        if rand % 2 == 0:
            print("{} is even".format(rand))
            print("{} is odd".format(rand))

    return num % 2

even_odd(5 #you chan change to the value you want
, start)

Hope I help!!!