Default Gulp task outputs errors.

Question

When I run gulp as a command I get the following errors:

assert.js:351
    throw err;
    ^

AssertionError [ERR_ASSERTION]: Task function must be specified
    at Gulp.set [as _setTask] (/Users/lisacrandall/Downloads/Stage1Video3/node_modules/undertaker/lib/set-task.js:10:3)
    at Gulp.task (/Users/lisacrandall/Downloads/Stage1Video3/node_modules/undertaker/lib/task.js:13:8)
    at Object.<anonymous> (/Users/lisacrandall/Downloads/Stage1Video3/gulpfile.js:10:6)
    at Module._compile (internal/modules/cjs/loader.js:721:30)
    at Object.Module._extensions..js (internal/modules/cjs/loader.js:732:10)
    at Module.load (internal/modules/cjs/loader.js:620:32)
    at tryModuleLoad (internal/modules/cjs/loader.js:560:12)
    at Function.Module._load (internal/modules/cjs/loader.js:552:3)
    at Module.require (internal/modules/cjs/loader.js:657:17)
    at require (internal/modules/cjs/helpers.js:22:18)

My code looks like this:

'use strict';

var gulp = require('gulp');

gulp.task("hello", function(done) {
    console.log("Hello!");
    done();
});

gulp.task("default", ["hello"], function() {
    console.log("This is the default task!");
});

Any help would be appreciated.

Answer 1 · 2019-04-11T11:56:42Z

April 11, 2019 11:56am

Gulp 4.0 has changed the way that tasks should be defined if the task depends on another task to execute. The list parameter has been deprecated.

Instead of the list parameter they have introduced gulp.series() and gulp.parallel().

https://github.com/gulpjs/gulp/blob/master/docs/recipes/running-tasks-in-series.md

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Lisa Crandall

Lisa Crandall

Default Gulp task outputs errors.

1 Answer

Dragosh Craciun

Dragosh Craciun