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Lisa Crandall
Lisa Crandall
3,409 Points

Default Gulp task outputs errors.

When I run gulp as a command I get the following errors:

    throw err;

AssertionError [ERR_ASSERTION]: Task function must be specified
    at Gulp.set [as _setTask] (/Users/lisacrandall/Downloads/Stage1Video3/node_modules/undertaker/lib/set-task.js:10:3)
    at Gulp.task (/Users/lisacrandall/Downloads/Stage1Video3/node_modules/undertaker/lib/task.js:13:8)
    at Object.<anonymous> (/Users/lisacrandall/Downloads/Stage1Video3/gulpfile.js:10:6)
    at Module._compile (internal/modules/cjs/loader.js:721:30)
    at Object.Module._extensions..js (internal/modules/cjs/loader.js:732:10)
    at Module.load (internal/modules/cjs/loader.js:620:32)
    at tryModuleLoad (internal/modules/cjs/loader.js:560:12)
    at Function.Module._load (internal/modules/cjs/loader.js:552:3)
    at Module.require (internal/modules/cjs/loader.js:657:17)
    at require (internal/modules/cjs/helpers.js:22:18)

My code looks like this:

'use strict';

var gulp = require('gulp');

gulp.task("hello", function(done) {

gulp.task("default", ["hello"], function() {
    console.log("This is the default task!");

Any help would be appreciated.

1 Answer

Gulp 4.0 has changed the way that tasks should be defined if the task depends on another task to execute. The list parameter has been deprecated.

Instead of the list parameter they have introduced gulp.series() and gulp.parallel().