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Jonathan Ambriz
Courses Plus Student 3,902 PointsDisplay is showing undefined for all room numbers. What do I need to do to my code? I am calling rooms[i].name..
I copied the code from the previous exercise as suggested and changed the code to refer to the rooms.json file. I also changed the classes to match the room's available status and am using the rooms[i].name.
2 Answers
Blaize Pennington
13,878 PointsYou are showing undefined because you are trying to open rooms[i].name. There is no key of name in the Json file. There is a key of room, so if you change that to rooms[i].room it fixes everything.
David Jalloh
Courses Plus Student 8,068 PointsstatusHTML += rooms[i].room;