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JavaScript JavaScript Basics (Retired) Making Decisions with Conditional Statements Improving the Random Number Guessing Game

Walter Cortez
Walter Cortez
4,071 Points
Posted by Walter Cortez
Walter Cortez
4,071 Points

Doesn't let me try again on higher numbers...

Why doesn't program let me try a second time if I guess on higher numbers?

Walter Cortez
Walter Cortez
4,071 Points
Walter Cortez
Walter Cortez
4,071 Points

...if I get number wrong on the first try?

1 Answer

Erik Nuber
Erik Nuber
20,629 Points
Erik Nuber
Erik Nuber
20,629 Points

You are missing a } It is rather confusing to try to explain so here it is and I marked where...

var correctGuess = false;
var randomNumber = Math.floor(Math.random() * 6 ) + 1;
var guess;

guess = prompt('I am thinking of a number between 1 and 6. What is it?');

if (parseInt(guess) === randomNumber ) {    
  correctGuess = true;
} else if (parseInt(guess) < randomNumber ) {
    guess = prompt('Try again. The number I am thinking of is greater than' + guess);  
    if (parseInt(guess) === randomNumber) {
        correctGuess = true;
    }  //MISSING THIS HERE
} else if (parseInt(guess) > randomNumber ) {
    guess = prompt('Try again. The number I am thinking of is less than' + guess);
    if (parseInt(guess) === randomNumber) {
    correctGuess = true;
}  
}

if (correctGuess) {
    document.write('<p>You guessed the number!</p>');
} else {
    document.write('<p>Sorry. The number was ' + randomNumber + '.</p>');
}
Walter Cortez
Walter Cortez
4,071 Points
Walter Cortez
Walter Cortez
4,071 Points

Thank you Erik will try that!