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Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

Posted by Edward Torres
Edward Torres
6,158 Points

Don't know how to solve this.

Can't figure out the solution.

minutes.py 
import datetime
def minutes(datetime1, datetime2)
    return round(10)((datetime2-datetime1).seconds/60)

1 Answer

Dan Johnson
Dan Johnson
40,532 Points
Dan Johnson
Dan Johnson
40,532 Points

Using:

round(10)((datetime2-datetime1).seconds/60)

Will attempt to pass the result of (datetime2-datetime1).seconds/60 as an argument to the result of round(10). Since round results in an int it can't be treated as a callable.

Besides that you do have the logic correct, so just apply the round function like this:

round( (datetime2-datetime1).total_seconds() / 60 )
Vittorio Somaschini
Vittorio Somaschini
33,371 Points
Vittorio Somaschini
Vittorio Somaschini
33,371 Points

Hi Edward Torres,

please also note that you are missing a colon in the function definition.

;)