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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

MEKA ANOOP
MEKA ANOOP
72 Points

error

cant find what is the wrong in that

Name.java
// I have setup a java.io.Console object for you named console
String firstName = console.readLine("Enter your name");

1 Answer

Simon Coates
Simon Coates
28,692 Points

it wants the string just as a literal:

String firstName = "MEKA";