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Python Python Basics (2015) Number Game App Even or Odd

even_odd(number)

Thank you in advance for your help!

John

even.py
def even_odd(number):    
    number = input("> ")
    if number % 2 == 0:
        print("False")
    else:
        print("True")

1 Answer

You don't need to get user input the test supplies a number to even_odd() when you click check work. Also print should be return.

def even_odd(number):
    if number % 2 == 0:  # Even numbers won't have a remainder.
        return(True)
    else:
        return(False)

Thank you very much John!!!

Have a great week!!!

John