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Python

Lucas Garcia
Lucas Garcia
6,612 Points
Posted by Lucas Garcia
Lucas Garcia
6,612 Points

FizzBuzz Challenge

Why aren't any of my if statements printing? When I run this the only thing that prints is the input for the user name and number entered. Thank you for your help!

name = input("Please enter your name: ") number = int(input("Please enter a number: ")) is_fizz = (number % 3 == 0) is_buzz = (number % 5 == 0) print("Your name is {}".format(name)) print("The number you entered is {}".format(number))

if number == is_fizz: print("{} is a Fizz number".format(number)) if number == is_buzz: print("{} is a buzz number".format(number)) if number == (is_fizz & is_buzz): print("{} is a FizzBuzz number".format(number))

Pierre Guiglion
Pierre Guiglion
11,583 Points

This condition if number == is_fizz: will always return False because your is_fizz and is_buzz are booleans, meaning either True or False.
But number is expected to be... well, a number, so nothing is printed.

1 Answer

Lucas Garcia
Lucas Garcia
6,612 Points
Lucas Garcia
Lucas Garcia
6,612 Points

Thank you Pierre Guiglion. I got it to work!

name = input("Please enter your name: ") number = int(input("Please enter a number: ")) is_fizz = (number % 3 == 0) is_buzz = (number % 5 == 0) is_fizzBuzz = ((number % 3 == 0) & (number % 5 == 0)) is_neither = ((number % 3 != 0) & (number % 5 != 0)) print("Your name is {}".format(name)) print("The number you entered is {}".format(number))

if is_fizzBuzz == True: print("{} is a FizzBuzz number".format(number)) elif is_fizz == True: print("{} is a Fizz number".format(number)) elif is_buzz == True: print("{} is a buzz number".format(number)) elif is_neither == True: print("{} is neither a fizzy or a buzzy number".format(number))