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Python Python for File Systems Project Starter Feeling Sluggish

function should accept two arguments, a string to make into an acceptable file or directory name, and a path.

Need help .

import os
import pathlib
import re
import sys

    '{PROJECT_SLUG}/REQUIRMENTS.TXT': 'requirements.txt.template',
    '{project_slug}/app.py': "app.py.template',
    '{project_slug}/static/css/{project_slug.css}': 'project.css.template',
    '{project_slug}/static/js/{project_slug}.js': 'project.js.template',
    '{project_slug}/templates/index.html': 'index.html.template'

def slugify(string, path):
    string = unicodedata.normalize('NFKC', string)
    string = re.sub(r'[^\w\s]', '',string).strip().lower()
    return re.sub(r'[_\-\s|+', '_', string)

def create_files(root, slug, name):       
    for file_name, template_name in FILES.items():
            template_file = open(os.path.join('templates', template_name))
            file_content = template_file.name()
            file_conten = flask_template_prepare(file_content)
            file_content = file_content.format(project_name=name, project_slug=slug)
            file_content = flask_template_repair(file_content)

            target_file = open(os.path.join(root, file_name.format(project_slug)), 'w')
        except OSError: 
            print("couldn't create {}".format(file_name.format(project_slug=slug)))

def main():
    project_root = get_root()
    project_name = None
    while not project_name:
        project_name = input("What's the full name for the project? ").strip()
    project_slug = slugify(project_name)

    create_dirs(project_root, project_slug)
    print("Creating {} in {}".format(project_name, project_root))

    if __name__ == '__main__':