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Margaret Johnson
Margaret Johnson
4,275 Points
Posted by Margaret Johnson
Margaret Johnson
4,275 Points

Gulp - how to loop through directories and perform same task on it's contents?

I want to compress SVGs that are used per page and then inject the compressed SVG stream into a file using a gulp task. I have directories such as ..svg/index , ...svg/about, etc. My current gulp task implementation hard codes the input and output directories and files. What is the best way to feed in a directory then do the task? Here is my current gulpfile.js:

'use strict';
const gulp = require('gulp');
const svgstore = require('gulp-svgstore');
const inject = require('gulp-inject');
const debug = require('gulp-debug');
const svgmin = require('gulp-svgmin');

// Useful functions.
function fileContents(filePath, file) {
  return file.contents.toString();
}
// Read in the SVGs used by index.html and inject the stream
// into index.html.
gulp.task('make_sprite_index',function(){
  // Compile the SVGs into a stream.
  var svgs = gulp
    .src('client/design/svg/index/*.svg')
    .pipe(debug())
    .pipe(svgmin())
    .pipe(svgstore({
        inlineSvg: true
      }))

  return gulp
    // Flask based server stores html in the templates folder.
    .src('client/design/html/index.html')
    .pipe(inject(svgs, {
      transform: fileContents
    }))
    .pipe(gulp.dest('templates'));

});
gulp.task('make_sprite_layout',function(){
  // Compile/minimize the SVGs into a stream.
  var svgs = gulp
    .src('client/design/svg/layout/*.svg')
    .pipe(debug())
    .pipe(svgmin())
    .pipe(svgstore({
        inlineSvg: true
      }))
  // return the file in the distribution directory after SVG has been injected.
  return gulp
    // Flask based server stores html in the templates folder.
    .src('client/design/html/layout.html')
    .pipe(inject(svgs, {
      transform: fileContents
    }))
    .pipe(gulp.dest('templates'));

});

thank you.