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PHP Build a Basic PHP Website (2018) Enhancing a Form Escaping Output

Posted by Michael Whalen
Michael Whalen
4,282 Points

Having trouble escaping $name for malicious code.

Added FILTER_SANITIZE_STRING, FILTER_SANITIZE_SPECIAL_CHARS, and if (isset($var)) echo $var. Still getting malicious code warning.

views_listing_edit.php 
<?php
      require_once("controllers_listing.php");
    $name = trim(filter_input(INPUT_POST,"name",FILTER_SANITIZE_STRING));
        $name = trim(filter_input(INPUT_POST,"link",FILTER_SANITIZE_STRING));
        $name = trim(filter_input(INPUT_POST,"description",FILTER_SANITIZE_SPECIAL_CHARS));
?>

<html>
<body>

    <h1>Edit Listing</h1>

    <form method="post">
        <table>
            <tr>
                <th>
                    <label for="name">Name</label>
                </th>
                <td><input type="text" id="name" name="name" value="
                    <?php
                        if (isset($name)) echo $name;
                    ?>">
                </td>
            </tr>
            <tr>
                <th>
                    <label for="Link">Link</label>
                </th>
                <td><input type="text" id="link" name="link" value="
                    <?php
                        if (isset($link)) echo $link;
                    ?>">
                </td>
            </tr>
            <tr>
                <th>
                    <label for="Description">Description</label>
                </th>
                <td>
                    <textarea id="description" name="description">
                        <?php
                                        if (isset($description)) echo $description;
                        ?>
                    </textarea>
                </td>
            </tr>    
        </table>
        <input type="submit" value="Save">
    </form>

</body>
</html>

1 Answer

Michael Whalen
Michael Whalen
4,282 Points
Michael Whalen
Michael Whalen
4,282 Points

Found the problem.