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Jupil Yoon
1,692 PointsHELP ON THIS TASK PLEASE!
This challenge is similar to an earlier one. Remember, though, I want you to practice! You'll probably want to use try and except on this one. You might have to not use the else block, though.
Write a function named squared that takes a single argument.
If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num).
If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples.
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim
def squared(num1):
try:
int(num1)
return num1 * num1
except:
return num1 * len(num1)
1 Answer
rshap
12,433 PointsYou didn't specify the type of error that you are expecting (I'm pretty sure that it's "TypeError", and I shortened the "try" block a bit).
def squared(num1):
try:
return int(num1) * num1
except TypeError:
return num1 * len(num1)
Jupil Yoon
1,692 PointsJupil Yoon
1,692 PointsSorry, your code isn't working. Also I don't see any reason to specify error, I know it is better to specify it in order to be notified what error occurred. Not specifying error just wouldn't let me know what kind of error occured.