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Python Python Basics (2015) Shopping List App Continue

kabirdas
kabirdas
1,976 Points
Posted by kabirdas
kabirdas
1,976 Points

Help with break and continue

Hi,

I'm having some trouble with the challenge task. Here is the challenge:

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

Am I using the break and continue correctly?

I've checked my indentation, and I'm not sure where else to look for an error.

I appreciate any help.

breaks.py 
def loopy(items):
    for item in items:
        if item[0] = "a":
            break
        else:
            continue
    print(item)

4 Answers

doesitmatter
doesitmatter
12,885 Points

Read the question carefully:

If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

In your code you break instead of continueing. Within your else clause there should be a print statement

kabirdas
kabirdas
1,976 Points
kabirdas
kabirdas
1,976 Points

Ohhh. Let me give that a try. I thought break skips that item and continues? Does it stop the function entirely?

doesitmatter
doesitmatter
12,885 Points

Yes break exits the loop. Continue goes to the next item of the list.

kabirdas
kabirdas
1,976 Points
kabirdas
kabirdas
1,976 Points

Ok I've change my code and it still is not correct:

def loopy(items): for item in items: if item[0] = "a": continue else: print(item)

doesitmatter
doesitmatter
12,885 Points

Right because you are using the assignment operator = instead of == for the comparison

kabirdas
kabirdas
1,976 Points
kabirdas
kabirdas
1,976 Points

Argh! I do that all the time!! Thank you so much for your time!!