How can I get multiple of 7's and show in results array? I am able to get the odd numbers from 1 to 100.

Question

var results: [Int] = []
for n in 1...100 {
    if n%2 == 1 {
        print(n)
    }
}
How can I get multiple of 7's and show in results array?  I am able to get the odd numbers from 1 to 100.
```logicalOperators.swift
var results: [Int] = []
for n in 1...100 {
    // Enter your code below
    if % 2 == 1 {
    print(results.append(n))
    }
    // End code 
}
```

Jason Anders · Answer

Hey Khalid,
For what the challenge wants, you will need two checks in the if statement. You need to check to see if the number being iterated over (n) is odd and if the number (n) is also a multiple of seven. So, first you will need to use the negation symbol (!) to check if the number is odd, and then another check to see if the number is a multiple of 7.
Below is the corrected code for you reference. I hope it will make sense. :)
```swift
var results: [Int] = []
for n in 1...100 {
    // Enter your code below
    if (n % 2 != 0) && (n % 7 == 0) {
    print(results.append(n))
    }
    // End code 
}
```
:dizzy:

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Khalid Naseem

Khalid Naseem

How can I get multiple of 7's and show in results array? I am able to get the odd numbers from 1 to 100.

1 Answer

Jason Anders

Jason Anders