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JavaScript JavaScript Foundations Arrays Methods: Part 2

jonathan amador
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.a{fill-rule:evenodd;}techdegree
jonathan amador
Full Stack JavaScript Techdegree Student 6,154 Points
Posted by jonathan amador
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jonathan amador
Full Stack JavaScript Techdegree Student 6,154 Points

how I can sort at the changeller 2?, Can someone help me with this?

I made some somethin like

saying1.sort(function(a){a.length}); them no idea how I can sort this methods

index.html 
<!DOCTYPE html>
<html lang="en">
  <head>
    <title> JavaScript Foundations: Arrays</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Arrays: Methods Part 1</h2>
    <script>
      var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
      var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
      saying1.reverse();
      saying2.sort(function(a){a.length});
    </script>
  </body>
</html>

2 Answers

Malik El Khoury
Malik El Khoury
9,143 Points
Malik El Khoury
Malik El Khoury
9,143 Points

That's the code you should use, on your saying 2 you should make a function which take 2 argument and then return the length of one mines the length of the other to sort them according to their length...

<!DOCTYPE html>
<html lang="en">
  <head>
    <title> JavaScript Foundations: Arrays</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Arrays: Methods Part 1</h2>
    <script>
      var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
      var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
      saying1.reverse();
      saying2.sort(function(a, b) { return a.length - b.length; });
    </script>
  </body>
</html>