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jonathan amador
Full Stack JavaScript Techdegree Student 6,154 Pointshow I can sort at the changeller 2?, Can someone help me with this?
I made some somethin like
saying1.sort(function(a){a.length}); them no idea how I can sort this methods
<!DOCTYPE html>
<html lang="en">
<head>
<title> JavaScript Foundations: Arrays</title>
<style>
html {
background: #FAFAFA;
font-family: sans-serif;
}
</style>
</head>
<body>
<h1>JavaScript Foundations</h1>
<h2>Arrays: Methods Part 1</h2>
<script>
var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
saying1.reverse();
saying2.sort(function(a){a.length});
</script>
</body>
</html>
2 Answers
Malik El Khoury
9,143 PointsThat's the code you should use, on your saying 2 you should make a function which take 2 argument and then return the length of one mines the length of the other to sort them according to their length...
<!DOCTYPE html>
<html lang="en">
<head>
<title> JavaScript Foundations: Arrays</title>
<style>
html {
background: #FAFAFA;
font-family: sans-serif;
}
</style>
</head>
<body>
<h1>JavaScript Foundations</h1>
<h2>Arrays: Methods Part 1</h2>
<script>
var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
saying1.reverse();
saying2.sort(function(a, b) { return a.length - b.length; });
</script>
</body>
</html>
jonathan amador
Full Stack JavaScript Techdegree Student 6,154 PointsThanks Malik, thanks, It was very usefull your answer
jonathan amador
Full Stack JavaScript Techdegree Student 6,154 Pointsjonathan amador
Full Stack JavaScript Techdegree Student 6,154 PointsThanks Malik, thanks, It was very usefull your answer