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Lukas Korol
2,649 PointsHow to do 5x5 table in JQuery?
Hi. I want to do 5x5 table like below in JQuery. Is there a more efficient way to do it? Without copy the same code 5x ?
<table>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
</table>
What I have:
// create a table in html document
var $table = $("<table></table>");
$("#table_view").append($table);
//create 5 rows in a table
var amountOfRows = 5;
for(var i=0; i<amountOfRows; i++)
{
var $row = $("<tr></tr>");
var $td1 = $("<td></td>");
var $td2 = $("<td></td>");
var $td3 = $("<td></td>");
var $td4 = $("<td></td>");
var $td5 = $("<td></td>");
$row.append($td1);
$row.append($td2);
$row.append($td3);
$row.append($td4);
$row.append($td5);
$table.append($row);
}
2 Answers
Colin Bell
29,679 PointsAdded some content so you can actually see the table, but I think this is what you are trying to do: jsbin example
Unsubscribed User
6,144 PointsWhat about trying a for loop inside your for loop ? With the same number (5), it could work ?