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Python Python Basics (2015) Shopping List App Continue

Posted by Marko Borenovic
Marko Borenovic
1,813 Points

I cant see where I did wrong

I can't figure out how to do this thing

breaks.py 
def loopy(items):
    # Code goes here
    loopy in items:
        if loopy.index(0) = "a":
            continue
            print(loopy)

1 Answer

Samuel Ferree
Samuel Ferree
31,722 Points
Samuel Ferree
Samuel Ferree
31,722 Points

you've made a few syntax errors. You need a "for" statement to start an iteration. your print statement is tabbed over to far and falls under your if statement, but it will never execute as it is preceded by a continue statement. Your function and iterator also have the same name, it's considered standard to name your iterator the singular of your list name. 

def loopy(items):
  for item in items: # use the singular of items as our iteration variable
    if item.index(0) = "a":
      continue
    print(item) # reduce tab count so this isn't part of the if block

Note: This just fixes your code, it doesn't necessarily pass the challenge. My enrollment is currently paused and I can't see exactly what the conditions are.

Marko Borenovic
Marko Borenovic
1,813 Points

Thank you very much :D but I still haven't passed the challenge.

This is the full challenge:

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".