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Java Java Basics Perfecting the Prototype Parsing Integers

Posted by Kyudong Lim
Kyudong Lim
528 Points

I just can't solve this and move on. Please give the answer.

Anybody?

ParsingInts.java 
int answer = Integer.parseInt ("answerToLife");

1 Answer

Steve Hunter
Steve Hunter
57,712 Points

You've pretty much done it - but lose the quotation marks. You're passing a variable into the parseInt function. Putting the quotation marks there make it a string which the function can't handle as it isn't numeric. The string "42" contained in answerToLife can be converted to a number, so parseInt will work on it. 

int answer = Integer.parseInt(answerToLife);

Make sense?

Steve.