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Python Python Basics (2015) Shopping List App Continue

a a
a a
1,101 Points
Posted by a a
a a
1,101 Points

I need hint on Challenge task.

Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member.

Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if item[0] = a:
            continue
        else:
            print(item)
        return

1 Answer

Aayush Mitra
Aayush Mitra
24,904 Points
Aayush Mitra
Aayush Mitra
24,904 Points

Hi a a!

Three small errors.

First, you need to make the = sign to a double = sign. Currently you are assigning a variable when you want to be checking whether something is equal to something:

==

Next, put quotes around the a. It is a string:

"a"

Finally, you do not need to to return anything, delete the return.

Here is how the code should look:

def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)

Hope this helps!

Thanks! :)