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JavaScript Practice forEach in JavaScript Practice forEach forEach Practice - 4

Posted by oafwifkeiw
oafwifkeiw
1,546 Points

I think this code should be accepted

Result is right and forEach IS used... :)

app.js 
const alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'.split('');
let noel = [];

// noel should be: ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
// Write your code below

alphabet
  .filter(letter => letter !== 'L')
  .forEach(letter => noel.push(letter))

1 Answer

Matthew Long
Matthew Long
28,407 Points
Matthew Long
Matthew Long
28,407 Points

Looks good other than the missing semicolon. However, I think the challenge wants you to focus on .forEach() so try something like:

const alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'.split('');
let noel = [];

alphabet.forEach(letter => {
  if (letter != "L") {
    noel.push(letter);
  }
});

You could always use the conditional operator if you want to stay clean like you had:

alphabet.forEach(letter => letter != "L" ? noel.push(letter) : null);