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Start your free trialManuel Hurtadp
372 PointsI'm having trouble logging the items in the array to the console in order from first parameter to the last.
I've tried nearly everything I could think of but the program tells me that the I'm not logging the numbers in order from first parameter on the left to the last.
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 0; i < temperatures.length; i += 1) {
var items = temperatures.shift();
console.log(items);
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
1 Answer
Amber Cyr
19,699 PointsI am a little confused by your question, but I am assuming you would like to output the values in the array from 10 sequentially to 100? if so, shift() would not be a good choice since it actually removes values from the 0 position in the list every time the loop runs. I would suggest if you want to output the sequential numbers to sort your list first then output the contents.
var temperatures = [100,90,99,80,70,65,30,10];
temperatures = temperatures.sort(function(a, b){return a-b});
for (var i = 0; i < temperatures.length; i += 1) {
console.log(temperatures[i]);
}
Manuel Hurtadp
372 PointsManuel Hurtadp
372 PointsThe solution is a lot more complicated than I expected, thanks a lot.