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Python Python Basics (2015) Shopping List App Continue

Posted by Austin Greed
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Austin Greed
Python Web Development Techdegree Student 1,966 Points

I'm not getting where i am wrong

ame idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
items = ['abc','xyz']
def loopy(items):
    # Code goes here
    for item in items:
        if item != 'abc':
            print(item)
        else    
            continue
loopy()

1 Answer

Rich Zimmerman
Rich Zimmerman
24,063 Points
Rich Zimmerman
Rich Zimmerman
24,063 Points

You can call an index of a string, like you can in a list. So you want to check that the first letter (index 0) is 'a', if its is.. skip it, otherwise print it.

for item in items:
    if item[0] == 'a':
        continue
    else:
        print(item)