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JavaScript AJAX Basics AJAX Concepts Finish the AJAX Request

Posted by Arsal Abdullah
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Arsal Abdullah
Front End Web Development Techdegree Student 9,748 Points

Im not really sure what im doing wrong

I believe I am using the open method correctly and on the right object? Any help would be greatly appreciated :)

app.js 
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
  request.open('GET','footer.html');
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

The open syntax is good, but it's currently placed inside the onreadystatechange function. It needs to be done after the definition of that function.