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JavaScript AJAX Basics (retiring) AJAX Concepts Finish the AJAX Request

Posted by MUZ140995 Portia Mazonde
MUZ140995 Portia Mazonde
6,454 Points

In app.js, we've added an AJAX callback function. You need to complete the request. Add the code to open the AJAX reques

In app.js, we've added an AJAX callback function. You need to complete the request. Add the code to open the AJAX request using the GET method and pointing to the 'footer.html' file.

app.js 
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

3 Answers

Juliette Tworsey
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Juliette Tworsey
Front End Web Development Techdegree Graduate 32,425 Points
Juliette Tworsey
.a{fill-rule:evenodd;}techdegree seal-36
Juliette Tworsey
Front End Web Development Techdegree Graduate 32,425 Points

You have to put the open request after the callback function:

var request = new XMLHttpRequest(); request.onreadystatechange = function () { if (request.readyState === 4) {

document.getElementById("footer").innerHTML = request.responseText;

} };

request.open('GET','footer.html',true);

Scott Jones
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.a{fill-rule:evenodd;}techdegree
Scott Jones
Full Stack JavaScript Techdegree Student 7,293 Points
Scott Jones
.a{fill-rule:evenodd;}techdegree
Scott Jones
Full Stack JavaScript Techdegree Student 7,293 Points

var request = new XMLHttpRequest(); request.onreadystatechange = function () { if (request.readyState === 4) { document.getElementById("footer").innerHTML = request.responseText; } }; request.open("GET", "footer.html"); <----- answer goes here

Calvin Miracle
Calvin Miracle
22,028 Points
Calvin Miracle
Calvin Miracle
22,028 Points

Ah, "var request" is not in the scope of the function..

I'd move var request = new XMLHttpRequest(); inside the function definition.

I hope this helps! Take care..

-- Cal

Jake Lundberg
Jake Lundberg
13,965 Points
Jake Lundberg
Jake Lundberg
13,965 Points

You still have not asked a question???