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Java Java Basics Getting Started with Java IO

Nathaniel Boonzaaijer
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Nathaniel Boonzaaijer
Full Stack JavaScript Techdegree Student 8,607 Points
Posted by Nathaniel Boonzaaijer
.a{fill-rule:evenodd;}techdegree
Nathaniel Boonzaaijer
Full Stack JavaScript Techdegree Student 8,607 Points

IO.java printf not working?

I watched the video 2 times and I have no idea what I did differently, please assist.

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.

String firstName = console.readLine();
String lastName = console.readLine();

console.printf("First name: %s\n");

1 Answer

Yusuf Mohamed
Yusuf Mohamed
2,631 Points
Yusuf Mohamed
Yusuf Mohamed
2,631 Points

First of all these challenges tends to be quite picky so don't add unnecessary stuff like the lastname string, it was never requested by you.

Secondly the error you is doing is that when you use %s you have to afterwards add which variable you're using because otherwise the compiler won't know what to add instead of %s. The correct code is 

// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine();


console.printf("First name: %s\n",
              firstName);

Please write back if you understood or not and if you have more questions just shoot.

Yusuf Mohamed
Yusuf Mohamed
2,631 Points

No Problemos.