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Java Java Basics Getting Started with Java IO

James Fan
James Fan
1,264 Points
Posted by James Fan
James Fan
1,264 Points

Java question

String firstName="Fan"; console.printf("First name: %s", firstName); why still says i foget to pass firstName parameter in printf method?

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
String firstName="Fan";
console.readLine("My firt name is "+firstName);
String lastName="James";
console.readLine("My name is " + firstName + " " +lastName);
console.printf("First name: %s", firstName);

2 Answers

K Cleveland
K Cleveland
21,839 Points
K Cleveland
K Cleveland
21,839 Points 
String firstName="Fan";
console.readLine("My firt name is "+firstName);

Hey! The reason why your code isn't passing is because of how the questions are set up. This is what the task says:

Declare a variable that is named the camel-cased version of "first name". Store the user's first name into this new variable using console.readLine.

You declared a String firstName and set the string to "Fan". However, the task is asking you to declare a variable and then store the name using console.readLine.

If I wanted to store a string from console.readLine, I might write something like this:

String myVariable;
myVariable  = console.readLine("This will get stored in myVariable");

Hope this helps! :)

James Fan
James Fan
1,264 Points
James Fan
James Fan
1,264 Points

thanks! i found the answer in the forum the same problem people asked.