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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

Landing Activity

Am stuck I want to update the Text View to use the Spaceship's type property

LandingActivity.java
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class LandingActivity extends Activity {

    public Button mThrustButton;
    public TextView mTypeLabel;
    public EditText mPassengersField;

    public Spaceship mSpaceship;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_landing);

        mThrustButton = (Button)findViewById(R.id.thrustButton);
        mTypeLabel = (TextView)findViewById(R.id.typeTextView);
        mPassengersField = (EditText)findViewById(R.id.passengersEditText);

      mSpaceship = new Spaceship("FIREFLY");// Add your code here!
    }
}
Spaceship.java
public class Spaceship {
    private String mType;
    private int mNumPassengers = 0;

    public String getType() {
      return mType;
    }

    public void setType(String type) {
      mType = type;
    }

    public int getNumPassengers() {
      return mNumPassengers;
    }

    public void setNumPassengers(int numPassengers) {
      mNumPassengers = numPassengers;
    }

    public Spaceship() {
      mType = "SHUTTLE";
    }

    public Spaceship(String type) {
      mType = type;
    }
}

1 Answer

Chase Marchione
Chase Marchione
155,055 Points

Hi Munyaradzi,

We're going to use the setText method to set the text of the mTypeLabel to the type used by mSpaceship. We'll use the getType method in order to get that type from mSpaceship.

mTypeLabel.setText(mSpaceship.getType());

Hope this helps!