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Python Python Basics (2015) Shopping List App Continue

Subramanian K
Subramanian K
3,103 Points
Posted by Subramanian K
Subramanian K
3,103 Points

Loopy function challenge

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

items = []

def list_adding(new_items):
    items.append(new_items)
    print("The newitem is {}".format(new_items))

def loopy(new_items):
    print('Here is the list of items')
    for new_items in items:
        if new_items[0] =='a':
            continue
            print("Sorry ! We can't accept name with starting letter a")
        else:
            list_adding(new_items)

while True:
    new_items = input("> ")
    loopy(new_items)

2 Answers

Antonio De Rose
Antonio De Rose
20,884 Points
Antonio De Rose
Antonio De Rose
20,884 Points

is this what you are after

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)
khamarul mokhtar
khamarul mokhtar
552 Points

items = []

def word_adding(new_items): items.append(new_items) print('the new items is {}'.format(new_items))

def loopy(new_items): for new_items in items: print(new_items)

while True: new_items = input('> ')

if new_items[0] == 'a':
    continue
elif new_items[0] != 'a':
    break
    print(new_items)


loopy(new_items)

hi antonio, im having problem with my code here, mind if you find out for for me ? thanks

Subramanian K
Subramanian K
3,103 Points
Subramanian K
Subramanian K
3,103 Points

Thanks man Antonio De Rose. I take it too complicated..