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Simingaye Dube2,587 Points
modify the command ,change it to display the value stored in the 'flavor' variable.
Modify the command that displays the flavor of ice cream. Instead of it displaying a static piece of text, change it to display the value stored in the 'flavor' variable.
<?php $flavor = "vanilla"; echo "<p>Your favorite flavor of ice cream is "; echo "vanilla"; echo ".</p>"; echo "<p>Hal's favorite flavor is cookie dough, also!</p>"; ?>
Shane Oliver19,977 Points
Here you need to replace the echo 'vanilla' with the variable $flavor - which holds the string value of 'vanilla'
try changing this: echo 'vanilla';
to: echo $flavor;