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Python

My if and elif statement is now working

The following code should be easy, but it is not working the way I intended. Can someone explain what I am doing wrong please? Thank you.

num = int(input("Enter a number: "))
n = num % 2

if (n != 0):
    print('Weird')
if (n == 0 and n == range(2,6)):
    print('Not Weird')
if (n == 0 and n == range(6,21)):
    print('Weird')
if (n > 20):
    print('Not Weird')

[MOD: added ```python formatting -cf]

Chris Freeman
Chris Freeman
Treehouse Moderator 68,468 Points

Can you state what unexpected behavior you are seeing?

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,468 Points

After running your code, I see the issue. The modulo operation % 2 will return a 0 for even numbers and a 1 for odd numbers. So if num is odd, you get "weird". If num is even, n is 0 and no if condition matches. Perhaps you meant to comparenum` to the range.

However, n == range() will always be false because you cannot compare an integer with and an iterable. Instead, check if the integer is in the range iterable:

#...
if (n == 0 and num in range(2,6)):
#...

Style tip: The parens around the if conditions are not strictly needed and are usually left off to improve readability.

Post back if you need more help. Good luck!!!