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Python Python Basics (2015) Shopping List App Continue

Michael Dinnall
Michael Dinnall
6,730 Points

Need help, got stuck for a while now. maybe i don't get the logic compltely

def loopy(items): for item in items: if item[0] == "a": print item

print loopy(items)

breaks.py
def loopy(items):
    for item in items:
     if item[0] == "a":
        print items

1 Answer

Hey Michael! The task is asking you to NOT print if the first char of item is 'a'. So, when the first char == 'a'. Skip it(continue). Else, print it. Here is how I solved it:

for item in items:
    if item[0] == 'a':
        continue
    else:
        print(item)

Cheers!

You could also simply do an if item[0] != 'a': to skip it, but your approach might be more "Pythonic".. I couldn't say.