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JavaScript JavaScript Foundations Variables Shadowing

Posted by Bla Blubb
Bla Blubb
2,740 Points

nick is the correct answer. but why??

why is nick correct???

person="nick" was set outside the function. person was not called variable.

so it must end up in a failure notice: person is not defined.

or not???

1 Answer

William Li
PLUS
William Li
Courses Plus Student 26,868 Points
William Li
William Li
Courses Plus Student 26,868 Points 
var person = "Jim";

function whosGotTheFunc() {
    var person = "Andrew";
}

person = "Nick";

whosGotTheFunc();

console.log(person);

Is this the code you're referring to? Nick is certainly the correct answer. Let me say a couple things about it.

  1. person variable was declared in the first line, person = "Nick"; just reassign it a different value.
  2. the statement var person = "Andrew"; inside the function whosGotTheFunc create another person variable local only to its function scope, which means this person variable is gone as soon as function invocation finished, and has nothing to do with the Global person variable outside of the function.