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Android Build a Blog Reader Android App Using Intents to Display and Share Posts Opening a Webpage in the Browser

Alex Lowe
Alex Lowe
15,147 Points
Posted by Alex Lowe
Alex Lowe
15,147 Points

Not sure how to tackle this code challenge

I'm trying to finish this course before it's retired. In the video we got a Json array from the json data, then a json object from the json array, then the url string from the json object. Here I'm not sure how to get a string from just an array to parse into my intent.

I know I'm off, but this is what I tried:

CustomListActivity.java 
import android.os.Bundle;
import android.widget.ArrayAdapter;
import android.view.View;
import android.view.ListView;
import android.content.Intent;
import android.net.Uri;

public class CustomListActivity extends ListActivity {

    protected String[] mUrls = { "http://www.teamtreehouse.com", "http://developer.android.com", "http://www.github.com" };

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_custom_list);

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, mUrls);
        setListAdapter(adapter);
    }

    @Override
    protected void onListItemClick(ListView l, View v, int position, long id) {
        // Add code here!
      super.onListItemClick(l, v, position, id);
      Intent intent = new Intent(Intent.ACTION_VIEW);
            String UrlString = mUrls.getString(position);
            intent.setData(Uri.parse(UrlString));
            startActivity(intent);
    }
}
Alex Lowe
Alex Lowe
15,147 Points
Alex Lowe
Alex Lowe
15,147 Points

Solved it like this: 

String UrlString = mUrls[position];
            Intent intent = new Intent(Intent.ACTION_VIEW);
            intent.setData(Uri.parse(UrlString));
            startActivity(intent);
    }