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Android Build an Interactive Story App Finishing the User Interface Using a Model in the Presenter

James Thomas
James Thomas
6,452 Points

Now that we have a model object, update the TextView to use the Spaceship's shipType property.

Could someone please let me know where I am going wrong, it's that time again where four hours of non stop treehouse has fried my brain.

Thanks

James.

LandingActivity.java
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class LandingActivity extends AppCompatActivity {

    public Button thrustButton;
    public TextView typeLabel;
    public EditText passengersField;

    public Spaceship spaceship;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_landing);

      spaceship = new Spaceship("FIREFLY");

        thrustButton = (Button)findViewById(R.id.thrustButton);
        typeLabel = (TextView) Spaceship.getShipType();
        passengersField = (EditText)findViewById(R.id.passengersEditText);

        // Add your code here!

    }
}
Spaceship.java
public class Spaceship {
    private String shipType;
    private int numPassengers = 0;

    public String getShipType() {
      return shipType;
    }

    public void setShipType(String shipType) {
      this.shipType = shipType;
    }

    public int getNumPassengers() {
      return numPassengers;
    }

    public void setNumPassengers(int numPassengers) {
      this.numPassengers = numPassengers;
    }

    public Spaceship() {
      shipType = "SHUTTLE";
    }

    public Spaceship(String shipType) {
      this.shipType = shipType;
    }
}

1 Answer

Melodie 1
Melodie 1
3,931 Points

typeLabel = (TextView) Spaceship.getShipType();

this is wrong , you need firstly to retrieve the View by using R.id. and then the id of the TextView.

after you do that , you need to call the setText() method which takes an id or a String