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Java Java Objects (Retired) Harnessing the Power of Objects Handling Exceptions

Posted by Carl Smith
Carl Smith
8,185 Points

Nt sure how to perform this catch method.

I think this is correct, however, I'm getting a syntax error. Any help would be appreciated.

Main.java 
public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
        }
        kart.drive(2);
      }
        catch (IllegalArgumentException iae) {
          System.out.printf("The error was: %s\n", iae.getMessage());
    }
}

1 Answer

Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

use:

public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
        }
        try { 
          kart.drive(2);
        } catch(IllegalArgumentException iae){
          System.out.println(iae.getMessage());
        }
    }
}

need to use a try keyword and {} to specify the area where the exception could occur. The catch block goes after the closing } of the try block.