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iOS Build a Playlist Browser with Swift Building the Music Library and Playlist Models Struct Initialization

Posted by ivanzdane
ivanzdane
6,541 Points

Optional unwrapping not working

When I run this line in a playground: title = playlistDictonary["title"] as String!

it returns: {Some "Runner's Rampage"}

To get the actual value, I need to unwrap the optional again on another line. What is the point of putting a "!" after String in the first line if it doesn't unwrap the optional?

1 Answer

Rasmus Rønholt
PLUS
Rasmus Rønholt
Courses Plus Student 17,358 Points
Rasmus Rønholt
Rasmus Rønholt
Courses Plus Student 17,358 Points

In my opinion it is pointless... So either define none optional properties or set them with optionals... Swift has changed syntax in this case, but I would set the title property with the following, which will handle cases where the data returned is NOT a string, without crashing...

title = playlistDictonary["title"] as? String