Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Aaron Gates
1,573 PointsPHP Arrays and Control Structures coding callenge
as i get to the end of the challenge, step 3, I complete the following and then it tells me that Task 1 is no longer passing. However, when I preview the work, it comes out as expected. I don't understand. Anyone! Bueller? Bueller?
<?php
//edit this array
$contacts = array( array ('name' => 'Alena Holligan', 'email' => 'alena.holligan@teamtreehouse.com'),
array ('name' => 'Dave McFarland', 'email' => 'dave.mcfarland@teamtreehouse.com'),
array ('name' => 'Treasure Porth', 'email' => 'treasure.porth@teamtreehouse.com'),
array ('name' => 'Andrew Chalkley', 'email' => 'andrew.chalkley@teamtreehouse.com'));
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>"$contacts[0]["name"], $contacts[0]["email"]"</li>\n";
echo "<li>"$contacts[1]["name"], $contacts[1]["email"]"</li>\n";
echo "<li>"$contacts[2]["name"], $contacts[2]["email"]"</li>\n";
echo "<li>"$contacts[3]["name"], $contacts[3]["email"]"</li>\n";
echo "</ul>\n";
1 Answer

ivana kantnerova
14,218 Pointsyou have to join variables and strings with help dots ... like joining strings
echo "<ul>\n"; echo "<li>".$contacts[0]["name"].' : '.$contacts[0]["email"]."</li>\n"; echo "<li>".$contacts[1]["name"].' : '.$contacts[1]["email"]."</li>\n"; echo "<li>".$contacts[2]["name"].' : '.$contacts[2]["email"]."</li>\n"; echo "<li>".$contacts[3]["name"].' : '.$contacts[3]["email"]."</li>\n"; echo "</ul>\n";
Julian Gutierrez
19,201 PointsJulian Gutierrez
19,201 PointsAnswered your question here